Hey math can help!
2006-07-05 17:01:59
So I was thinking about how fast the pieces stack up when you have more than one column that needs an I piece. Before i explained that you should not let yourself be to determined to clear your Tetris in one place, but as we all know there should be only one place to require a tetris peice. Meaning every hole should have two or less pieces to fill it in fully. Except, of course, the one you plan to get a tetris with.So i started to throw some numbers in there to solve about when should we get I pieces.
Ok lets look at the facts
1. Each piece contains 4 little blocks
2. There are 10 little blocks in a row
3. For a Tetris there must be at leat 4 high by 9 wide
4. According to colour_thief the generator gives us all 7 pieces in a random order.
So if you leave one open in order to set up a tetris you must have (9*4)=36 small pieces are needed before one Tetris can be set up
36/4= 9 so by those odds in 9 pieces you should have at least one I piece (at least in an average scenario)
Lets say you set it up so you need two I pieces to get one Tetris, so it requires that you will have to go through about 14 pieces until you can get one Tetris.
But how how will it stack? 14-2(straight pieces)=12
12*4= 48 (little pieces) 48/8 (pieces across the bottom)= 6 rows up.
By having one I piece needed you can only have 4 lines (less than, actually) before you get the I piece for the tetris. That is much better then needing 6 and barley getting the two I pieces.
So now that you got to think again, (its like were back in school!) i hope i jogged your memory, proved something interesting about Tetris and showed that math can help, when necessary. :)
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